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If (5x^2 + 65x + 60)/(x^2 +10x - 24) = (5x + 5)/(x - 2), the
[#permalink]
20 Nov 2017, 11:26

Question Stats:

If \(\frac{(5x^2 + 65x + 60)}{(x^2 +10x - 24)} = \frac{(5x + 5)}{(x - 2)}\), then which of the following are possible values of x?

A. −60

B. −12

C. −1

D. 1

E. 2

F. 5

Kudos for correct solution.

A. −60

B. −12

C. −1

D. 1

E. 2

F. 5

Show: :: OA

A, C, D, and F

Kudos for correct solution.

Re: If (5x^2 + 65x + 60)/(x^2 +10x - 24) = (5x + 5)/(x - 2), the
[#permalink]
28 Nov 2017, 03:26

Need either a closer look or discerning eye to get solution on the fly otherwise its would literally waste much time

Re: If (5x^2 + 65x + 60)/(x^2 +10x - 24) = (5x + 5)/(x - 2), the
[#permalink]
29 Nov 2017, 05:46

1

1

Bookmarks

Bunuel wrote:

If \(\frac{(5x^2 + 65x + 60)}{(x^2 +10x - 24)} = \frac{(5x + 5)}{(x - 2)}\), then which of the following are possible values of x?

A. −60

B. −12

C. −1

D. 1

E. 2

F. 5

A. −60

B. −12

C. −1

D. 1

E. 2

F. 5

Show: :: OA

A, C, D, and F

Here the equation can be written as-

\(\frac{5(x^2 + 13x + 12)}{(x^2 +10x - 24)} = \frac{5(x + 1)}{(x - 2)}\)

or \(\frac{(x^2 + 13x + 12)}{(x^2 +10x - 24)} = \frac{(x + 1)}{(x - 2)}\)

or \(\frac{(x + 12)(x+1)}{(x + 12)(x-2)} = \frac{(x + 1)}{(x - 2)}\)

Now looking at the values we notice only when x=2 & x =-12, the equation is not possible, rest all are the possible values.

_________________

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Re: If (5x^2 + 65x + 60)/(x^2 +10x - 24) = (5x + 5)/(x - 2), the
[#permalink]
14 Jun 2019, 08:14

1

pranab01 wrote:

Bunuel wrote:

If \(\frac{(5x^2 + 65x + 60)}{(x^2 +10x - 24)} = \frac{(5x + 5)}{(x - 2)}\), then which of the following are possible values of x?

A. −60

B. −12

C. −1

D. 1

E. 2

F. 5

A. −60

B. −12

C. −1

D. 1

E. 2

F. 5

Show: :: OA

A, C, D, and F

Here the equation can be written as-

\(\frac{5(x^2 + 13x + 12)}{(x^2 +10x - 24)} = \frac{5(x + 1)}{(x - 2)}\)

or \(\frac{(x^2 + 13x + 12)}{(x^2 +10x - 24)} = \frac{(x + 1)}{(x - 2)}\)

or \(\frac{(x + 12)(x+1)}{(x + 12)(x-2)} = \frac{(x + 1)}{(x - 2)}\)

or \(\frac{(x+1)}{(x-2)} = \frac{(x + 1)}{(x - 2)}\).

Now looking at the values we notice only when x=2, the equation is not possible, reset all are the possible values.

also, x=-12 gives undefined value, so this is also not possible

Re: If (5x^2 + 65x + 60)/(x^2 +10x - 24) = (5x + 5)/(x - 2), the
[#permalink]
14 Jun 2019, 22:18

jelal123 wrote:

also, x=-12 gives undefined value, so this is also not possible

Thanks. might be an oversight

_________________

Rules for Posting

Got 20 Kudos? You can get Free GRE Prep Club Tests

GRE Prep Club Members of the Month:TOP 10 members of the month with highest kudos receive access to 3 months GRE Prep Club tests

Re: If (5x^2 + 65x + 60)/(x^2 +10x - 24) = (5x + 5)/(x - 2), the
[#permalink]
20 Sep 2021, 08:46

Hello from the GRE Prep Club BumpBot!

Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.

Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.

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