Answer :

Given:

Distance of the ladder from the wall, d = BC = 1.5 m

Angle of elevation, θ = 60°

To find: Height of the wall, h:

Solution:

Let AC be the ladder and B be the foot of the wall.

In right angled Δ ABC,

tan [θ] = Opposite / Adjacent

Here θ = 60°

And also the opposite side is AB and the adjacent side is BC

∴ tan 60 ^{ o } = AB/BC

tan 60 ^{ o } = AB/BC

AB = BC tan 60 ^{ o }

We know that BC = 1.5m

= 1.5 × (√ 3)

= 1.5 × 1.732

= 2.598 m

Therefore the height of the wall is 2.598 m.

Rate this question :

How useful is this solution?

We strive to provide quality solutions. Please rate us to serve you better.

Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Expertsview all courses

Dedicated counsellor for each student

24X7 Doubt Resolution

Daily Report Card

Detailed Performance Evaluation

RELATED QUESTIONS :

Draw the graph ofNCERT - Mathematics